X^2+3x-598=0

Solution for X^2+3x-598=0 equation:

X^2+3X-598=0

a = 1; b = 3; c = -598;
Δ = b2-4ac
Δ = 32-4·1·(-598)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-49}{2*1}=\frac{-52}{2}
=-26
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+49}{2*1}=\frac{46}{2}
=23
$